2/x+4-4/x-3=-4/x^2+x-12

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Solution for 2/x+4-4/x-3=-4/x^2+x-12 equation: 



2/x+4-4/x-3=-4/x^2+x-12

We move all terms to the left:

2/x+4-4/x-3-(-4/x^2+x-12)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2+x-12)!=0

x∈R



We add all the numbers together, and all the variables

2/x-4/x-(-4/x^2+x-12)+1=0

We get rid of parentheses

2/x-4/x+4/x^2-x+12+1=0

We calculate fractions

We do not support expression: x^3

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